25x^2-125x+150=4x^2

Solution for 25x^2-125x+150=4x^2 equation:

25x^2-125x+150=4x^2

We move all terms to the left:

25x^2-125x+150-(4x^2)=0

determiningTheFunctionDomain
25x^2-4x^2-125x+150=0

We add all the numbers together, and all the variables

21x^2-125x+150=0

a = 21; b = -125; c = +150;
Δ = b2-4ac
Δ = -1252-4·21·150
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-55}{2*21}=\frac{70}{42}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+55}{2*21}=\frac{180}{42}
=4+2/7
$